Each iteration of for_each_child_of_node puts the previous node, but in the case of a return from the middle of the loop, there is no put, thus causing a memory leak. Hence add an of_node_put before the return in two places. Issue found with Coccinelle. Signed-off-by: Nishka Dasgupta <nishkadg.linux@xxxxxxxxx> --- drivers/pinctrl/sprd/pinctrl-sprd.c | 9 +++++++-- 1 file changed, 7 insertions(+), 2 deletions(-) diff --git a/drivers/pinctrl/sprd/pinctrl-sprd.c b/drivers/pinctrl/sprd/pinctrl-sprd.c index c31b58168772..5abb64da2c0d 100644 --- a/drivers/pinctrl/sprd/pinctrl-sprd.c +++ b/drivers/pinctrl/sprd/pinctrl-sprd.c @@ -940,8 +940,10 @@ static int sprd_pinctrl_parse_dt(struct sprd_pinctrl *sprd_pctl) for_each_child_of_node(np, child) { ret = sprd_pinctrl_parse_groups(child, sprd_pctl, grp); - if (ret) + if (ret) { + of_node_put(child); return ret; + } *temp++ = grp->name; grp++; @@ -950,8 +952,11 @@ static int sprd_pinctrl_parse_dt(struct sprd_pinctrl *sprd_pctl) for_each_child_of_node(child, sub_child) { ret = sprd_pinctrl_parse_groups(sub_child, sprd_pctl, grp); - if (ret) + if (ret) { + of_node_put(sub_child); + of_node_put(child); return ret; + } *temp++ = grp->name; grp++; -- 2.19.1