Re: [PATCH] GPIO: Add GPIO support for the ACCES 104-IDIO-16

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On 10/05/2015 04:29 AM, Linus Walleij wrote:
>> +struct a_104_idio_16_gpio {
>> +       struct gpio_chip chip;
>> +       spinlock_t lock;
>> +       unsigned base;
> 
> Isn't this void __iomem *base?

The 'base' member is used to hold the I/O port base address passed to the
inb/outb functions for port-mapped I/O operations. Since the addresses are
not dereferenced, I don't believe an __iomem pointer would be correct.

>> +static const unsigned A_104_IDIO_16_EXTENT = 8;
> 
> Looks like it could be a #define A_104_IDIO_16_EXTENT 8

I used a const variable for the benefit of type-safety; I assumed the
compiler would optimize it. What is the advantage of a #define constant?

>> +static void __exit a_104_idio_16_exit(void)
>> +{
>> +       pr_info("104-idio-16: Exiting 104-idio-16 module\n");
>> +
>> +       gpiochip_remove(&gp.chip);
> 
> Where is that &gp.chip? Not in this file. Nor should you use any globals.
> 

I agree that using a global data structure isn't good practice, but I'm not
sure how else to expose the gpio_chip structure in the respective module
_init and _exit functions since they have void parameter lists. Would it be
more appropriate to use the platform device API in this situation to avoid
the global data structure?

>> +static int a_104_idio_16_gpio_get(struct gpio_chip *chip, unsigned offset)
>> +{
>> +       struct a_104_idio_16_gpio *a104i16gp = to_a104i16gp(chip);
>> +       const unsigned BIT_MASK = 1U << (offset-16);
>> +
>> +       if (offset < 16)
>> +               return 0;
> 
> Always return 0, why? Is that really correct?

GPIO 0-15 are output-only. The kerneldoc for 'struct gpio_chip' states that
for output signals the get function should return the value actually sensed,
or zero. Since I cannot sense the output signals, I return zero in these cases.
Is this behavior correct?

- William

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