Nick Piggin:
> > Isn't it path.dentry->d_inode instead of nd.inode?
:::
> It should be the inode we followed, rather than the inode of the
> new path, I think.
In __do_follow_link(), path.dentry is what we followed, isn't it?
__do_follow_link()
{
struct dentry *dentry = path->dentry;
;;;
*p = dentry->d_inode->i_op->follow_link(dentry, nd);
;;;
J. R. Okajima
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