> > > > +void __init efi_memmap_free(phys_addr_t mem, unsigned int
> > > > num_entries)
> > > > +{
> > > > + unsigned long size = num_entries * efi.memmap.desc_size;
> > > > + unsigned int order = get_order(size);
> > > > + phys_addr_t end = mem + size - 1;
> > > > +
> > > > + if (slab_is_available()) {
> > > > + __free_pages(pfn_to_page(PHYS_PFN(mem)), order);
> > > How do you know that the memory you are freeing was allocated when
> > > slab_is_available() was already true?
> > >
> > efi_memmap_free() should be used *only* in conjunction
> > with efi_memmap_alloc()(As I explicitly didn't mention this, maybe it
> > might
> > have confused you).
> >
> > When allocating memory efi_memmap_alloc() does similar check
> > for slab_is_available() and if so, it allocates memory using
> > alloc_pages().
> > So, to free pages allocated using alloc_pages(), efi_memmap_free()
> > uses __free_pages().
> >
> I understand that. But by abstracting away the free() routine as well
> as the alloc() routine, you are hiding this fact.
>
> What is preventing me from using efi_memmap_alloc() to allocate space
> for the memmap, and using efi_memmap_free() in another place? How are
> you preventing that this does not happen in a way where mm_init() may
> be called in the mean time?
>
> Whether __free_pages() should be used or memblock_free() is a property
> of the *allocation* itself, not of whether mm_init() has already been
> called. So if (!slab_is_available()), you can use memblock_free().
> However, if (slab_is_available()), you cannot use __free_pages()
> because the allocation could have been made before mm_init() was
> called.
>
Aahh.. Thanks a lot! for making it clear. I see the bug now
(efi_memmap_alloc() could be called before mm_init() in which case it uses
memblock_alloc() where as efi_memmap_free() could be called after mm_init() in
which case it uses __free_pages()).
I will fix this.
Regards,
Sai
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