On Thu, Nov 03, 2016 at 11:20:08PM +0100, Jason A. Donenfeld wrote: > Hi David, > > On Thu, Nov 3, 2016 at 6:08 PM, David Miller <davem@xxxxxxxxxxxxx> wrote: > > In any event no piece of code should be doing 32-bit word reads from > > addresses like "x + 3" without, at a very minimum, going through the > > kernel unaligned access handlers. > > Excellent point. In otherwords, > > ctx->r[0] = (le32_to_cpuvp(key + 0) >> 0) & 0x3ffffff; > ctx->r[1] = (le32_to_cpuvp(key + 3) >> 2) & 0x3ffff03; > ctx->r[2] = (le32_to_cpuvp(key + 6) >> 4) & 0x3ffc0ff; > ctx->r[3] = (le32_to_cpuvp(key + 9) >> 6) & 0x3f03fff; > ctx->r[4] = (le32_to_cpuvp(key + 12) >> 8) & 0x00fffff; > > should change to: > > ctx->r[0] = (le32_to_cpuvp(key + 0) >> 0) & 0x3ffffff; > ctx->r[1] = (get_unaligned_le32(key + 3) >> 2) & 0x3ffff03; > ctx->r[2] = (get_unaligned_le32(key + 6) >> 4) & 0x3ffc0ff; > ctx->r[3] = (get_unaligned_le32(key + 9) >> 6) & 0x3f03fff; > ctx->r[4] = (le32_to_cpuvp(key + 12) >> 8) & 0x00fffff; > I agree, and the current code is wrong; but do note that this proposal is correct for poly1305_setrkey() but not for poly1305_setskey() and poly1305_blocks(). In the latter two cases, 4-byte alignment of the source buffer is *not* guaranteed. Although crypto_poly1305_update() will be called with a 4-byte aligned buffer due to the alignmask set on poly1305_alg, the algorithm operates on 16-byte blocks and therefore has to buffer partial blocks. If some number of bytes that is not 0 mod 4 is buffered, then the buffer will fall out of alignment on the next update call. Hence, get_unaligned_le32() is actually needed on all the loads, since the buffer will, in general, be of unknown alignment. Note: some other shash algorithms have this problem too and do not handle it correctly. It seems to be a common mistake. Eric -- To unsubscribe from this list: send the line "unsubscribe linux-crypto" in the body of a message to majordomo@xxxxxxxxxxxxxxx More majordomo info at http://vger.kernel.org/majordomo-info.html
