SH> ckpt_hdr_put(ctx, in) ?
Oops.
>> + un->this = ckpt_obj_lookup_add(ctx, sk, CKPT_OBJ_SOCK, &new);
>> + if (un->this < 0)
>> + goto out;
>> +
>> + if (sk->peer)
>> + un->peer = ckpt_obj_lookup_add(ctx, pr, CKPT_OBJ_SOCK, &new);
>> + else
>> + un->peer = 0;
>> +
>> + if (un->peer < 0) {
>> + ret = un->peer;
>> + goto out;
>> + }
SH> So what if new == 1 for either un->this or un->peer? You never
SH> actually write them out to the checkpoint image?
On the checkpoint run, the new flag doesn't matter to us (and isn't
used here). Am I missing something?
SH> ckpt_hdr_put(ctx, un) ?
Oops.
SH> ckpt_hdr_socket_in(ctx, in)?
I think you mean:
ckpt_hdr_put(ctx, in);
and if so: Oops :)
--
Dan Smith
IBM Linux Technology Center
email: danms@xxxxxxxxxx
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