Balbir Singh wrote:
>>> How, it works out fine in my calculation
>>>
>>> 50 + 40 for G2 and G3, make sure that G1 gets 10%, since others are
>>> limited to 90%
>>> 50 + 40 for G1 and G3, make sure that G2 gets 10%, since others are
>>> limited to 90%
>>> 50 + 50 for G1 and G2, make sure that G3 gets 0%, since others are
>>> limited to 100%
>>>
>>>
>> It's fine in that it satisfies the guarantees, but it is deeply
>> suboptimal. If I ran a cpu hog in the first group, while the other two
>> were idle, it would be limited to 50% cpu. On the other hand, if it
>> consumed all 100% cpu it would still satisfy the guarantees (as the
>> other groups are idle).
>>
>> The result is that in such a situation, wall clock time would double
>> even though cpu resources are available.
>>
>
> But then there is no other way to make a *guarantee*, guarantees come
> at a cost of idling resources, no? Can you show me any other
> combination that will provide the guarantee and without idling the
> system for the specified guarantees?
>
Suppose in my example cgroup 1 consumed 100% of the cpu resources and
cgroup 2 and 3 were completely idle. All of the guarantees are met (if
cgroup 2 is idle, there's no need to give it the 10% cpu time it is
guaranteed).
If your only tool to achieve the guarantees is a limit system, then
yes, the equation yields the correct results. But given that it yields
such inferior results, I think we need to look for a more involved solution.
I think the limits method fits cases where it is difficult to evict a
resource (say, disk quotas -- if you want to guarantee 10% of space to
cgroups 1, you must limit all others to 90%). But for processor usage,
you can evict a cgroup instantly, so nothing prevents a cgroup from
consuming all available resources as long as others do not contend for them.
--
I have a truly marvellous patch that fixes the bug which this
signature is too narrow to contain.
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