Tim Walberg wrote: > Maybe you want "(bytes * 100) / size"? However, if int and size_t are 32-bit, that will overflow at around 20 or 40 MB (20 for signed, 40 for unsigned), which isn't really all that much. Converting to either double or long long might be wise, i.e. percent = (int)(bytes * 100.0) / size; or: percent = (int)(bytes * 100LL) / size; -- Glynn Clements <glynn@xxxxxxxxxxxxxxxxxx> -- To unsubscribe from this list: send the line "unsubscribe linux-c-programming" in the body of a message to majordomo@xxxxxxxxxxxxxxx More majordomo info at http://vger.kernel.org/majordomo-info.html
