What are the typical values of bytes and size? Suspect
"(bytes / size)", being integer division, probably truncates
to 0 if size is relatively large...
Maybe you want "(bytes * 100) / size"? Or as another
alternative (arithmetically approximately equivalent,
but not quite as clear, however, it saves on multiply
operations):
size = size / 100;
...
...
...
printf(... bytes / size);
On 09/08/2009 21:40 +0700, Randi Botse wrote:
>> hi all,
>>
>> ....
>> int fd, fdp;
>> unsigned int size;
>> int progress = 0;
>> size_t bytes = 0;
>> void *buffer;
>> ....
>>
>> /* open fd from a device then create fdp, allocate buffer,, etc. */
>>
>> while (bytes < size) {
>> ret = read(fd, buffer + bytes, size - bytes);
>> if (ret == -1) {
>> perror("read");
>> return -1;
>> }
>> ret = write(fdp, buffer + bytes, ret);
>> if (ret == -1) {
>> perror("write");
>> return -1;
>> }
>> bytes += ret;
>>
>> progress = (int) ((bytes / size) * 100);
>> printf("\rcompleted: %i%%", progress);
>> fflush(stdout);
>> }
>>
>> ....
>>
>> I run this loop to receive some data, the printf() seem not updated,
>> the progress output is
>> always in it's initial value until the loop was finished. but when i do...
>>
>> progress = (int) ((bytes / 2) * 100); /* change size to 2 (or random number) */
>>
>> then it's works... what's wrong here???
>> --
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