Fabio Miranda Hamburger wrote: > I am trying to implement a 100% math function ( avoid handle the float as > a char array), that remove x number of decimals from the right to the > float point. That is a meaningless specification. > Example: > Given x= 12345.6789 I call the function with (x,2) and the returned number > is: x= 12345.67, for (x,4) returned value is x=12345 So presumably if x = 12345.67890000, f(x,2) would be 12345.678900 and f(x,4) would be 12345.6789. But all of those numbers are the same. Also, bear in mind that you cannot exactly represent 0.1 (or, more generally, 10^(-n) for any n >= 1) in floating-point. E.g. storing 12345.6789 as a single-precision value will result in: 12345.67871093750000000000000000000000000000000000000000... while a double-precision value will give: 12345.67890000000079453457146883010864257812500000000000... Per's suggestion of *keeping* a given number of decimal places is feasible. -- Glynn Clements <glynn@xxxxxxxxxxxxxxxxxx> - : send the line "unsubscribe linux-c-programming" in the body of a message to majordomo@xxxxxxxxxxxxxxx More majordomo info at http://vger.kernel.org/majordomo-info.html
