Fabio Miranda Hamburger wrote:
Hello,
I am trying to implement a 100% math function ( avoid handle the float
as a char array), that remove x number of decimals from the right to the
float point.
Example:
Given x= 12345.6789 I call the function with (x,2) and the returned
number is: x= 12345.67, for (x,4) returned value is x=12345
I was trying to implement this function using datatype casting, abs()
and other functions from math.h library.
How about :
double f( double x, int n )
{
return ( n>0 ? f( x*10,n-1 )/10 : floor(x) );
}
Oops, 'n' is number of decimals you want to keep, not throw away.
/Per Jessen, Zurich
-
: send the line "unsubscribe linux-c-programming" in
the body of a message to majordomo@xxxxxxxxxxxxxxx
More majordomo info at http://vger.kernel.org/majordomo-info.html
