Sunday, 26 March 2006 16:27 samaye, Steve Graegert alekhiit:
> Because the format (the string to display) is provided as a constant
> expression and it is not being modified:
> printf("%s\n", "abc");
> printf("%s\n", mystring);
> In both cases the format argument is a constant string.
Why, the following works as well:
#include "stdio.h"
void main(void)
{
char s[10] = "\n%s\n\n";
printf(s, "hello");
}
Here s is not a const char *. It is a variable char *. That actually compiled
and executed. So probably it's only because the printf *function* does not
change the value (and *should* not change the value during parsing, I
presume).
--
Tux #395953 resides at http://samvit.org
playing with KDE 3.51 on SUSE Linux 10.0
$ date [] CCE +2006-03-26 W12-7 UTC+0530
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