I'm trying to set up a mirror of two Samsung 840 Pro 256GB SSDs as a cache device. Per their specs, the page size is 8k, and the erase block size is 1024k, so I created the cache device as: make-bcache --wipe-bcache -b 1024k -w 8k -C /dev/md2 With a bucket size equal to the erase block, and a block size equal to the page size. The documentation on block size wasn't really clear, but I believe it's supposed to equal the ssd page size, ie, the minimum io size for the device. However, when trying to register this cache device, it fails with: bcache: register_bcache() error opening /dev/md2: Bad block/bucket size Looking at the code: err = "Bad block/bucket size"; if (!is_power_of_2(sb->block_size) || sb->block_size > PAGE_SECTORS || !is_power_of_2(sb->bucket_size) || sb->bucket_size < PAGE_SECTORS) goto err; and given PAGE_SIZE = 4096 and PAGE_SECTORS = 8, it's complaining that my cache device block size of 8k is greater than the page size of 4k. I guess I could create my cache device with a block size of 4k to make it work, but that seems inefficient as it does not match the page size. What's this limitation about? Can it be changed? Are SSD's with a > 4k page size just poor choices for a cache device? Thanks... -- To unsubscribe from this list: send the line "unsubscribe linux-bcache" in the body of a message to majordomo@xxxxxxxxxxxxxxx More majordomo info at http://vger.kernel.org/majordomo-info.html