On Wed, Jul 22, 2020 at 02:58:24PM +0000, Alex Belits wrote:
> From: Yuri Norov <ynorov@xxxxxxxxxxx>
>
> If CPU runs isolated task, there's no any backlog on it, and
> so we don't need to flush it.
What guarantees that we have no backlog on it?
> Currently flush_all_backlogs()
> enqueues corresponding work on all CPUs including ones that run
> isolated tasks. It leads to breaking task isolation for nothing.
>
> In this patch, backlog flushing is enqueued only on non-isolated CPUs.
>
> Signed-off-by: Yuri Norov <ynorov@xxxxxxxxxxx>
> [abelits@xxxxxxxxxxx: use safe task_isolation_on_cpu() implementation]
> Signed-off-by: Alex Belits <abelits@xxxxxxxxxxx>
> ---
> net/core/dev.c | 7 ++++++-
> 1 file changed, 6 insertions(+), 1 deletion(-)
>
> diff --git a/net/core/dev.c b/net/core/dev.c
> index 90b59fc50dc9..83a282f7453d 100644
> --- a/net/core/dev.c
> +++ b/net/core/dev.c
> @@ -74,6 +74,7 @@
> #include <linux/cpu.h>
> #include <linux/types.h>
> #include <linux/kernel.h>
> +#include <linux/isolation.h>
> #include <linux/hash.h>
> #include <linux/slab.h>
> #include <linux/sched.h>
> @@ -5624,9 +5625,13 @@ static void flush_all_backlogs(void)
>
> get_online_cpus();
>
> - for_each_online_cpu(cpu)
> + smp_rmb();
What is it ordering?
> + for_each_online_cpu(cpu) {
> + if (task_isolation_on_cpu(cpu))
> + continue;
> queue_work_on(cpu, system_highpri_wq,
> per_cpu_ptr(&flush_works, cpu));
> + }
>
> for_each_online_cpu(cpu)
> flush_work(per_cpu_ptr(&flush_works, cpu));
Thanks.
