On Wed, Mar 13, 2019 at 03:23:59PM +0000, Patrick Bellasi wrote: > On 13-Mar 15:09, Peter Zijlstra wrote: > > On Fri, Feb 08, 2019 at 10:05:40AM +0000, Patrick Bellasi wrote: > > > +static inline void uclamp_rq_update(struct rq *rq, unsigned int clamp_id) > > > +{ > > > + struct uclamp_bucket *bucket = rq->uclamp[clamp_id].bucket; > > > + unsigned int max_value = uclamp_none(clamp_id); > > > > That's 1024 for uclamp_max > > > > > + unsigned int bucket_id; > > > + > > > + /* > > > + * Both min and max clamps are MAX aggregated, thus the topmost > > > + * bucket with some tasks defines the rq's clamp value. > > > + */ > > > + bucket_id = UCLAMP_BUCKETS; > > > + do { > > > + --bucket_id; > > > + if (!rq->uclamp[clamp_id].bucket[bucket_id].tasks) > > > + continue; > > > + max_value = bucket[bucket_id].value; > > > > but this will then _lower_ it. That's not a MAX aggregate. > > For uclamp_max we want max_value=1024 when there are no active tasks, > which means: no max clamp enforced on CFS/RT "idle" cpus. > > If instead there are active RT/CFS tasks then we want the clamp value > of the max group, which means: MAX aggregate active clamps. > > That's what the code above does and the comment says. That's (obviously) not how I read it... maybe something like: static inline void uclamp_rq_update(struct rq *rq, unsigned int clamp_id) { struct uclamp_bucket *bucket = rq->uclamp[clamp_id].bucket; int i; /* * Since both min and max clamps are max aggregated, find the * top most bucket with tasks in. */ for (i = UCLMAP_BUCKETS-1; i>=0; i--) { if (!bucket[i].tasks) continue; return bucket[i].value; } /* No tasks -- default clamp values */ return uclamp_none(clamp_id); } would make it clearer?