Re: [PATCH 3/3] ACPI / PCI / PM: Rework acpi_pci_propagate_wakeup()

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On Friday, July 21, 2017 10:44:30 PM Rafael J. Wysocki wrote:
> On Friday, July 21, 2017 06:45:03 PM Andy Shevchenko wrote:
> > On Fri, Jul 21, 2017 at 3:42 PM, Rafael J. Wysocki <rjw@xxxxxxxxxxxxx> wrote:
> > 
> > > The acpi_pci_propagate_wakeup() routine is there to handle cases in
> > > which PCI bridges (or PCIe ports) are expected to signal wakeup
> > > for devices below them, but currently it doesn't do that correctly.
> > >
> > > The problem is that acpi_pci_propagate_wakeup() uses
> > > acpi_pm_set_device_wakeup() for bridges and if that routine is
> > > called for multiple times to disable wakeup for the same device,
> > > it will disable it on the first invocation and the next calls
> > > will have no effect (it works analogously when called to enable
> > > wakeup, but that is not a problem).
> > >
> > > Now, say acpi_pci_propagate_wakeup() has been called for two
> > > different devices under the same bridge and it has called
> > > acpi_pm_set_device_wakeup() for that bridge each time.  The
> > > bridge is now enabled to generate wakeup signals.  Next,
> > > suppose that one of the devices below it resumes and
> > > acpi_pci_propagate_wakeup() is called to disable wakeup for that
> > > device.  It will then call acpi_pm_set_device_wakeup() for the bridge
> > > and that will effectively disable remote wakeup for all devices under
> > > it even though some of them may still be suspended and remote wakeup
> > > may be expected to work for them.
> > >
> > > To address this (arguably theoretical) issue, allow
> > > wakeup.enable_count under struct acpi_device to grow beyond 1 in
> > > certain situations.  In particular, allow that to happen in
> > > acpi_pci_propagate_wakeup() when wakeup is enabled or disabled
> > > for PCI bridges, so that wakeup is actually disabled for the
> > > bridge when all devices under it resume and not when just one
> > > of them does that.
> > 
> > > -       if (wakeup->enable_count > 0)
> > > -               goto out;
> > > +       if (wakeup->enable_count > 0) {
> > > +               if (wakeup->enable_count < max_count)
> > > +                       goto inc;
> > > +               else
> > > +                       goto out;
> > > +       }
> > 
> > Wouldn't be simpler
> 
> I'm not really sure what you mean.
> 
> In general, ->
> 
> >     if (wakeup->enable_count >= max_count)
> >       goto out;
> 
> -> this is unlikely and ->>
> 
> >     if (wakeup->enable_count > 0)
> >       goto inc;
> 
> ->> this isn't.
> 
> Why would checking an unlikely condition before a likely one covering it
> ever be better?

OK, the common case is max_cout == 1 and it that case
enable_count >= max_count is equivalent to enable_count > 0,
so I guess fair enough.

Thanks,
Rafael

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