Hi, I have a Linux machine with kernel 2.6 and 3 network cards. I would like to ask what rules should I have in the routing table so that: 192.168.254.0/25 is routed through eth1 192.168.254.128/25 is routed through eth2 eth0 is my internal interface and eth1/eth2 are the external interfaces. * What is particulary specific for this case is that ipaddr_eth1 is in the same network as ipaddr_eth2 and that ipaddr_gateway_eth1 is the same as ipaddr_gateway_eth2. Here is what I have done so far: r2 root # ip rule ls 0: from all lookup local 32764: from 192.168.254.0/25 lookup 230 32765: from 192.168.254.128/25 lookup 231 32766: from all lookup main 32767: from all lookup default r2 root # ip route ls A.B.C.0/24 dev eth2 proto kernel scope link src A.B.C.X A.B.C.0/24 dev eth1 proto kernel scope link src A.B.C.Y 192.168.254.0/24 dev eth0 proto kernel scope link src 192.168.254.1 default via A.B.C.D dev eth1 r2 root # ip route ls table 230 A.B.C.0/24 dev eth1 scope link src A.B.C.X A.B.C.0/24 dev eth0 scope link src 192.168.254.1 default via A.B.C.D dev eth1 r2 root # ip route ls table 231 A.B.C.0/24 dev eth2 scope link src A.B.C.Y A.B.C.0/24 dev eth0 scope link src 192.168.254.1 default via A.B.C.D dev eth2 As a result the network segment 192.168.254.128/25 does not have access to Internet. Any ideas why? Is it a problem that eth1 is in the same network as eth2? Thanks in advance, -- Kamen TOMOV _______________________________________________ LARTC mailing list / LARTC@xxxxxxxxxxxxxxx http://mailman.ds9a.nl/mailman/listinfo/lartc HOWTO: http://lartc.org/
