On 04/21/2011 04:49 PM, Nguyen Thai Ngoc Duy wrote:
Hi,
I have a specialized e1000 device driver that expects to receive a
single frame per interrupt, no more. It's by design and very hard to
change (and it does not serve IP traffic). -net socket or tap can
sometimes deliver more than one frame in a row and blow up the driver
in turn. I'd like to experiment with tap/socket to only call
qemu_send_packet..() once and leave pending frames in queue until next
time, with hope that guest will have time to process the frame.
I don't understand how the driver can expect that. The card is free to
deliver multiple packets per interrupt. Are you counting on fast timing
to process the packet before the next packet arrives?
If you restrict the number of buffers you provide to the card to exactly
one, you'll get one packet per interrupts (and dropped packets).
The problem is I'm new to kvm and not sure how the main loop is run.
Will there be guest execution time between two tap/socket polls, how
long is it? Or is guest run in parallel with the event loop and
qemu_set_irq() somehow signals guest immediately?
The latter, it's in parallel.
Are you using qemu-kvm or qemu? qemu-kvm will deliver better interrupt
performance.
--
error compiling committee.c: too many arguments to function
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