On Wed, 9 Jun 2021 08:54:45 -0300 Jason Gunthorpe <jgg@xxxxxxxxxx> wrote: > On Wed, Jun 09, 2021 at 11:11:17AM +0200, Paolo Bonzini wrote: > > On 09/06/21 10:51, Enrico Weigelt, metux IT consult wrote: > > > On 08.06.21 21:00, Jason Gunthorpe wrote: > > > > > > > Eg I can do open() on a file and I get to keep that FD. I get to keep > > > > that FD even if someone later does chmod() on that file so I can't > > > > open it again. > > > > > > > > There are lots of examples where a one time access control check > > > > provides continuing access to a resource. I feel the ongoing proof is > > > > the rarity in Unix.. 'revoke' is an uncommon concept in Unix.. > > > > > > Yes, it's even possible that somebody w/ privileges opens an fd and > > > hands it over to somebody unprivileged (eg. via unix socket). This is > > > a very basic unix concept. If some (already opened) fd now suddenly > > > behaves differently based on the current caller, that would be a break > > > with traditional unix semantics. That's not the scenario here, this would work as expected. It's not a matter of who uses the fd it's that a property of the fd that provided elevated access has been removed. I only need to look as far as sudo to find examples of protocols where having access at some point in time does not guarantee ongoing access. If we go back to the wbinvd ioctl mechanism, if I call that ioctl with an ioasidfd that contains no devices, then I shouldn't be able to generate a wbinvd on the processor, right? If I add a device, especially in a configuration that can generate non-coherent DMA, now that ioctl should work. If I then remove all devices from that ioasid, what then is the difference from the initial state. Should the ioctl now work because it worked once in the past? If we equate KVM to the process access to the ioctl, then a reference or notification method should be used to retain or mark the end of that access. This is no different than starting a shell via sudo (ie. an ongoing reference) or having the previous authentication time out, or in our case be notified it has expired. > > That's already more or less meaningless for both KVM and VFIO, since they > > are tied to an mm. > > vfio isn't supposed to be tied to a mm. vfio does accounting against an mm, why shouldn't it be tied to an mm? Maybe you mean in the new model where vfio is just a device driver? Thanks, Alex