Hi Jan,
On 07.04.2015 10:43, Jan Kiszka wrote:
On 2015-04-05 19:12, Valentine Sinitsyn wrote:
Hi Jan,
On 05.04.2015 13:31, Jan Kiszka wrote:
studying the VM exit logic of Jailhouse, I was wondering when AMD's
vmload/vmsave can be avoided. Jailhouse as well as KVM currently use
these instructions unconditionally. However, I think both only need
GS.base, i.e. the per-cpu base address, to be saved and restored if no
user space exit or no CPU migration is involved (both is always true for
Jailhouse). Xen avoids vmload/vmsave on lightweight exits but it also
still uses rsp-based per-cpu variables.
So the question boils down to what is generally faster:
A) vmload
vmrun
vmsave
B) wrmsrl(MSR_GS_BASE, guest_gs_base)
vmrun
rdmsrl(MSR_GS_BASE, guest_gs_base)
Of course, KVM also has to take into account that heavyweight exits
still require vmload/vmsave, thus become more expensive with B) due to
the additional MSR accesses.
Any thoughts or results of previous experiments?
That's a good question, I also thought about it when I was finalizing
Jailhouse AMD port. I tried "lightweight exits" with apic-demo but it
didn't seem to affect the latency in any noticeable way. That's why I
decided not to push the patch (in fact, I was even unable to find it now).
Note however that how AMD chips store host state during VM switches are
implementation-specific. I did my quick experiments on one CPU only, so
your mileage may vary.
Regarding your question, I feel B will be faster anyways but again I'm
afraid that the gain could be within statistical error of the experiment.
It is, at least 160 cycles with hot caches on an AMD A6-5200 APU, more
towards 600 if they are colder (added some usleep to each loop in the test).
Great, thanks. Could you post absolute numbers, i.e how long do A and B
take on your CPU?
Valentine
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