On 10/02/2021 10:35, Chris Wilson wrote:
Quoting Tvrtko Ursulin (2021-02-10 09:37:55)
+static struct clients *aggregated_clients(struct clients *clients)
+{
+ struct client *ac, *c, *cp = NULL;
+ struct clients *aggregated;
+ int tmp, num = 0;
+
+ /* Sort by pid first to make it easy to aggregate while walking. */
+ sort_clients(clients, client_pid_cmp);
You could eliminate this tiny bit of duplication by always calling
aggregated_clients() and returning here for !aggregate_pids.
Okay, I did something like that.
+ aggregated = calloc(1, sizeof(*clients));
+ assert(aggregated);
+
+ ac = calloc(clients->num_clients, sizeof(*c));
+ assert(ac);
+
+ aggregated->num_classes = clients->num_classes;
+ aggregated->class = clients->class;
+ aggregated->client = ac;
+
+ for_each_client(clients, c, tmp) {
+ unsigned int i;
+
+ if (c->status == FREE)
+ break;
+
+ assert(c->status == ALIVE);
+
+ if ((cp && c->pid != cp->pid) || !cp) {
+ ac = &aggregated->client[num];
+
+ /* New pid. */
+ ac->clients = aggregated;
+ ac->status = ALIVE;
+ ac->id = ++num;
+ ac->pid = c->pid;
+ strcpy(ac->name, c->name);
+ strcpy(ac->print_name, c->print_name);
+ ac->engines = c->engines;
+ ac->val = calloc(clients->num_classes,
+ sizeof(ac->val[0]));
+ assert(ac->val);
+ ac->samples = 1;
+ }
+
+ cp = c;
+
+ if (c->samples < 2)
+ continue;
+
+ ac->samples = 2; /* All what matters for display. */
+ ac->total_runtime += c->total_runtime;
+ ac->last_runtime += c->last_runtime;
+
+ for (i = 0; i < clients->num_classes; i++)
+ ac->val[i] += c->val[i];
+ }
+
+ aggregated->num_clients = num;
+ aggregated->active_clients = num;
+
+ return sort_clients(aggregated, client_cmp);
}
Ok, that works very well. Hmm. The sort order does seem a little jumpy
though. May I suggest ac->id = -c->pid; instead of num;
Done it although I thought 1st pass being sort by pid already, num as id
would follow a stable order. I guess your point was inversion to
preserve order when cycling sort modes?
Regards,
Tvrtko
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