On Feb 28, 2011, at 10:40 AM, Bob Hinden wrote: > Pete, > > On Feb 27, 2011, at 11:32 PM, Pete Resnick wrote: > >> I'm sorry, but how could this *not* be posted to the IETF list? >> >> <http://xkcd.com/865/> > > I did a rough calculation and think they would have not run out of IPv6 addresses :-) > > I assumed a nanobot was 1 x 10^-6 M^2 and the surface of the earth was 5.1 x 10^11 M^2 (from Wikipedia). This means it would take 5.1 x 10^17 nanobots to cover the earth. The IPv6 address space is 3.4 x 10^38. Of course, I assumed only one layer deep. > > Bob Yes, but I think the nanobots are supposed to devour the entire earth, so it's volume that counts. The volume is about 1x10^21 m^3. So 40% is 4 x 10^20 m^3. 3.4 x 10^38 nanobots comes to 8.5 x 10^17 nanobots per m^3, or about 1.17 microns^3 per nanobot. Sounds about right. _______________________________________________ Ietf mailing list Ietf@xxxxxxxx https://www.ietf.org/mailman/listinfo/ietf