Hi, Chris,
On Mon, Oct 8, 2018 at 7:28 PM Chris Moller <moller@xxxxxxxxxxxxxx> wrote:
>
> /
> |
> |-----> disk1
> |
> |
> |-------X-----------> folder1
> |--------------------> folder2
> |-----> disk2
> |
> |--------------------> folder3
> |--------------------> folder4
> |--------------------> subdir
> |
> |--------------------> folder5
> |--------------------> folder6
>
>
>
>
> From that, folder1 would have an indices value of [0, 0], folder2 would be inidices[0, 1], folder3 [1,0], folder4 [1,1]
So folder1 will have row 0, column 0?
But that's wrong, because folder1 is at row 2 column 2.
>
> By extension, folder5 would be indices[1,2,0] and folder6 [1, 2, 1]
And folder5 should be at row 8 column 3.
And what is the coordinate be for disk1?
It should be row 1, column 1, right?
So as you can see I'm trying to get a value of the column number.
On top of that I will need to get a column 1 if I click where the "X" is
on the diagram...
Thank you.
>
> On 08/10/2018 18:25, Igor Korot wrote:
>
> Ok.
> Now let's get back.
>
> Do you know how I can get the column from the screenshot I sent?
>
> On Mon, Oct 8, 2018, 5:04 PM Chris Moller <moller@xxxxxxxxxxxxxx> wrote:
>>
>> Sorry, I misunderstood you.
>>
>> Actually, my daughter speaks pretty good Russian--she was a competitive figure skater for a lot of years and both her principal coaches were Russian. The preferred Russian over English so my daughter learned Russian. Anyway, she translated the songs years ago just to practise.
>>
>> On 08/10/2018 17:15, Igor Korot wrote:
>>
>> On Mon, Oct 8, 2018 at 4:09 PM Chris Moller <moller@xxxxxxxxxxxxxx> wrote:
>>
>> The ones by the Soviet Army? No. They're from a recording made in London in about 1959. Once upon a time, back in the 60s, I had an LP version that had some translations printed on the liner, but that LP vanished decades ago. Other than Tipperary, Annie Laurie, and Oh no, John!, they're in Russian.
>>
>> I understand.
>> And that's why I offer to translate them to English if you are interested.
>>
>> Thank you.
>>
>> On 08/10/2018 16:13, Igor Korot wrote:
>>
>> Chris,
>>
>> On Mon, Oct 8, 2018 at 3:08 PM Chris Moller <moller@xxxxxxxxxxxxxx> wrote:
>>
>> Here's a more complex tree, some of of the files in my music collection. (It's not exactly how GTK would show it, but close enough.)
>>
>> Do you want a translation for some those songs?
>>
>> ── misc
>> │ ├── PiSymphony
>> │ │ ├── Pi-and-e.ogg
>> │ │ └── The-Circle.ogg
>> │ └── SovietArmy
>> │ ├── 01 - Song of Youth.mp3
>> │ ├── 02 - A birch tree in a field did stand.mp3
>> │ ├── 03 - Far Away.mp3
>> │ ├── 04 - Song of the Volga Boatmen.mp3
>> │ ├── 05 - You are always beautiful.mp3
>> │ ├── 06 - Along Peter's Street.mp3
>> │ ├── 07 - Tipperary (sung in English).mp3
>> │ ├── 08 - Ah! Lovely Night.mp3
>> │ ├── 09 - Kamarinskaya [instrumental].mp3
>> │ ├── 10 - Annie Laurie (sung in English).mp3
>> │ ├── 11 - Song of the Plains (Meadowland).mp3
>> │ ├── 12 - Kalinka.mp3
>> │ ├── 13 - Bandura (sung in Ukrainian).mp3
>> │ ├── 14 - Oh no, John! (sung in English).mp3
>> │ ├── 15 - Snowflakes.mp3
>> │ ├── 16 - Ukrainian Poem.mp3
>> │ └── 17 - Soldiers' Chorus (from The Decembrists).mp3
>> └── synthesiser
>> ├── Carlos
>> │ ├── Aurora_Borealis.ogg
>> │ ├── Midnight_Sun.ogg
>> │ └── SonicSeasonings.ogg
>> ├── Hyman
>> │ ├── Evening_Thoughts.ogg
>> │ ├── Four_Duets_in_Odd_Meter.ogg
>> │ ├── Give_It_Up_or_Turn_It_Loose.ogg
>> │ ├── Improvisation_in_Fourths.ogg
>> │ ├── Kolumbo.ogg
>> │ ├── Tap_Dance_in_the_Memory_Banks.ogg
>> │ ├── The_Legend_of_Johnny_Pot.ogg
>> │ ├── The_Minotaur.ogg
>> │ ├── The_Moog_and_Me.ogg
>> │ ├── Time_Is_Tight.ogg
>> │ ├── Topless_Dancers_of_Corfu.ogg
>> │ └── Total_Bells_and_Tony.ogg
>> ├── Kitaro
>> │ ├── Silk_Road_II.ogg
>> │ └── Silk_Road_I.ogg
>> ├── Tomita
>> │ ├── Compilation
>>
>>
>> On 08/10/2018 14:48, Igor Korot wrote:
>>
>> On Mon, Oct 8, 2018 at 12:11 PM Chris Moller <moller@xxxxxxxxxxxxxx> wrote:
>>
>> Hi, Igor,
>>
>> The row-activated handler calls:
>>
>> void
>> user_function (GtkTreeView *tree_view,
>> GtkTreePath *path,
>> GtkTreeViewColumn *column,
>> gpointer user_data)
>> {
>>
>> }
>>
>> so what you need is :
>>
>> gint *indices = gtk_tree_path_get_indices (path);
>>
>> which will return an integer vector ow the row, column, sub-column, subsub-column... depending on the topgraphy of your tree. (You can get the depth of the tree--thus the number of entries in the vector--with:
>>
>> gint len = gtk_tree_path_get_depth (path);
>>
>> )
>>
>> If it's a simple two-dimensional tree, the column number will be indices[1], but you might want to make sure that the tree depth is at least two before doing that or you might be pointing past the end of the indices array.
>>
>> BTW, what do you mean by saying: "simple 2-dimensional tree"?
>> Is there going to be n-dimensional tree? How it will be represented on
>> the screen? Do you have a screenshot?
>>
>> Thank you.
>>
>> By the way, don't try to free the indices array--it points to a GTK internal structure.
>>
>> HTH,
>> Chris
>>
>>
>>
>> On 08/10/2018 12:52, Igor Korot wrote:
>>
>> Hi, Chris,
>>
>> On Sun, Oct 7, 2018 at 3:34 PM Chris Moller <moller@xxxxxxxxxxxxxx> wrote:
>>
>> Take a look at
>>
>> gint * gtk_tree_path_get_indices (GtkTreePath *path);
>>
>> with the "GtkTreePath *path" parameter you get from the row-activated callback.
>>
>> https://developer.gnome.org/gtk3/stable/GtkTreeModel.html#gtk-tree-path-get-indices
>>
>> I tried to do:
>>
>> int column = gtk_tree_path_get_indices( column );
>>
>> but got an error:
>>
>> Can't convert GtkTreeViewColumjn to GtkTreePath
>>
>> The "row-activated" callback is defined as:
>>
>> void user_function(GtkTreeView *tree_view, GtkTreePath *path,
>> GtkTreeViewColumn *column, gpointer user_data);
>>
>> And so the types are unrelated.
>>
>> What am I doling wrong?
>>
>> Thank you.
>>
>>
>>
>>
>> On 07/10/2018 20:04, Igor Korot via gtk-list wrote:
>>
>> Hi, ALL,
>> For the GtkTreeView there is a "row-activated" signal:
>> https://developer.gnome.org/gtk3/stable/GtkTreeView.html#GtkTreeView-row-activated.
>>
>> That function receives as a parameter
>>
>> column the GtkTreeViewColumn in which the activation occurred.
>>
>> The problem is (at least as I see it) is that it is not a simple integer
>> for the column number.
>>
>> Is there a simple way to get a column number on which I activated
>> the row from this signal?
>>
>> Thank you.
>> _______________________________________________
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>>
>>
>>
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>>
>>
>>
>>
>>
>>
>>
>
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