Re: [PATCH] Fix deletion of last character in levenshtein distance

[Date Prev][Date Next][Thread Prev][Thread Next][Date Index][Thread Index]

 



Hi,

On Wed, 19 Nov 2008, Samuel Tardieu wrote:

> * Johannes Schindelin <Johannes.Schindelin@xxxxxx> [2008-11-19 01:53:45 +0100]
> 
> | Hi,
> | 
> | On Tue, 18 Nov 2008, Samuel Tardieu wrote:
> | 
> | > diff --git a/levenshtein.c b/levenshtein.c
> | > index db52f2c..98fea72 100644
> | > --- a/levenshtein.c
> | > +++ b/levenshtein.c
> | > @@ -25,7 +25,7 @@ int levenshtein(const char *string1, const char *string2,
> | >  					row2[j + 1] > row0[j - 1] + w)
> | >  				row2[j + 1] = row0[j - 1] + w;
> | >  			/* deletion */
> | > -			if (j + 1 < len2 && row2[j + 1] > row1[j + 1] + d)
> | > +			if (row2[j + 1] > row1[j + 1] + d)
> | 
> | I do not understand: does row2 have more entries than len2?
> 
> Yes it does: int *row2 = xmalloc(sizeof(int) * (len2 + 1));
> 
> | In any case, you will _have_ to guard against accessing elements
> | outside the reserved memory.
> 
> Why would that be needed? j belongs to [0, len2[, so j+1 is always
> in [0, len2+1[ which is ok for both row2 and row1.

Okay, I understand now, _after_ having looked at the original 
levenshtein.c.

IOW you could have made my task of reviewing your patch much easier.

Anyway, here is my

	Acked-by: Johannes Schindelin <johannes.schindelin@xxxxxx>

Thanks for the bugfix,
Dscho

--
To unsubscribe from this list: send the line "unsubscribe git" in
the body of a message to majordomo@xxxxxxxxxxxxxxx
More majordomo info at  http://vger.kernel.org/majordomo-info.html

[Index of Archives]     [Linux Kernel Development]     [Gcc Help]     [IETF Annouce]     [DCCP]     [Netdev]     [Networking]     [Security]     [V4L]     [Bugtraq]     [Yosemite]     [MIPS Linux]     [ARM Linux]     [Linux Security]     [Linux RAID]     [Linux SCSI]     [Fedora Users]

  Powered by Linux