On Wed, Feb 3, 2021 at 8:55 AM Hongyi Zhao <hongyi.zhao@xxxxxxxxx> wrote:
>
> On Wed, Feb 3, 2021 at 1:09 AM Junio C Hamano <gitster@xxxxxxxxx> wrote:
> >
> > Hongyi Zhao <hongyi.zhao@xxxxxxxxx> writes:
> >
> > > On Tue, Feb 2, 2021 at 1:41 PM Junio C Hamano <gitster@xxxxxxxxx> wrote:
> > >>
> > >> You can, on _your_ end, filter incoming messages that are sent via
> > >> vger.kernel.org and do not have your address on To or Cc.
> > >
> > > Thank you very much for your comment. It seems that the following
> > > Gmail filter will do the trick:
> > >
> > > From: *@vger.kernel.org
> > > To or Cc: -hongyi.zhao@xxxxxxxxx
> > >
> > > But I can't find the Cc field on the filter panel.
> >
> > Here is what I use to process messages that are sent to me without
> > being sent to the mailing list:
> >
> > (to:gitster@xxxxxxxxx -(to:git@xxxxxxxxxxxxxxx))
> >
> > The rule is set to skip the inbox and throw it in dustbin ;-).
> >
> > I'd imagine something like
> >
> > (-(to:hongyi.zhao@xxxxxxxxx) (to:git@xxxxxxxxxxxxxxx))
> >
> > would hit what you want to filter out. Let me swap To/Cc of this
> > message so that you would appear on Cc so that you can experiment; I
> > think to: would work for such a message just fine as well.
>
> Thanks a lot for your wonderful notes. Based on my trial and error
> with Gmail's filter/search toolbar, It seems that the correct filter
> should be written as follows to meet my requirements:
>
> to:(git@xxxxxxxxxxxxxxx) -{hongyi.zhao@xxxxxxxxx}
> to:(git@xxxxxxxxxxxxxxx) -hongyi.zhao@xxxxxxxxx
NB, you can also change the "@" to ".", they are equivalent in the
filtering result, as shown below:
to:(git.vger.kernel.org) -{hongyi.zhao.gmail.com}
to:(git.vger.kernel.org) -hongyi.zhao.gmail.com
Best
--
Assoc. Prof. Hongyi Zhao <hongyi.zhao@xxxxxxxxx>
Theory and Simulation of Materials
Hebei Polytechnic University of Science and Technology engineering
NO. 552 North Gangtie Road, Xingtai, China
