On 2 February 2017 at 20:19, G. Sylvie Davies <sylvie@xxxxxxxxxxxxxxx> wrote: > On Thu, Feb 2, 2017 at 9:51 AM, Hilco Wijbenga <hilco.wijbenga@xxxxxxxxx> wrote: >> Hi all, >> >> I'm trying to get the committer date printed in a custom fashion. >> Using "%cI" gets me close: >> >> $ git show --format="%cI | %an" master | head -n 1 >> 2017-01-31T17:02:13-08:00 | Hilco Wijbenga >> >> I would like to get rid of the "-08:00" bit at the end of the >> timestamp. According to the "git show" manual I should be able to use >> "%<(<N>[,trunc|ltrunc|mtrunc])" to drop that last part. >> >> $ git show --format="%<(19,trunc)cI | %an" master | head -n 1 >> cI | Hilco Wijbenga >> >> Mmm, it seems to be recognized as a valid "something" but it's not >> working as I had expected. :-) I tried several other versions of this >> but no luck. Clearly, I'm misunderstanding the format description. How >> do I get "2017-01-31T17:02:13 | Hilco Wijbenga" to be output? >> > > Will this work for you? > > $ git show -s --pretty='%cd | %an' --date=format:%FT%R:%S > 2017-02-02T10:01:36 | G. Sylvie Davies Ah, that does indeed do exactly what I want. Thank you. > I have no idea how portable this might be. As "git help log" says: > > --date=format:... feeds the format ... to your system > strftime. Use --date=format:%c to show the date in your system > locale’s preferred format. See the strftime manual for a complete list > of format placeholders. It should be fine for my purposes. Any idea why "%<(19,trunc)cl" doesn't work? (Your solution solves my original problem perfectly but I'd like to understand how I'm misreading the spec.)