On Thu, Feb 2, 2017 at 9:51 AM, Hilco Wijbenga <hilco.wijbenga@xxxxxxxxx> wrote:
> Hi all,
>
> I'm trying to get the committer date printed in a custom fashion.
> Using "%cI" gets me close:
>
> $ git show --format="%cI | %an" master | head -n 1
> 2017-01-31T17:02:13-08:00 | Hilco Wijbenga
>
> I would like to get rid of the "-08:00" bit at the end of the
> timestamp. According to the "git show" manual I should be able to use
> "%<(<N>[,trunc|ltrunc|mtrunc])" to drop that last part.
>
> $ git show --format="%<(19,trunc)cI | %an" master | head -n 1
> cI | Hilco Wijbenga
>
> Mmm, it seems to be recognized as a valid "something" but it's not
> working as I had expected. :-) I tried several other versions of this
> but no luck. Clearly, I'm misunderstanding the format description. How
> do I get "2017-01-31T17:02:13 | Hilco Wijbenga" to be output?
>
Will this work for you?
$ git show -s --pretty='%cd | %an' --date=format:%FT%R:%S
2017-02-02T10:01:36 | G. Sylvie Davies
I have no idea how portable this might be. As "git help log" says:
--date=format:... feeds the format ... to your system
strftime. Use --date=format:%c to show the date in your system
locale’s preferred format. See the strftime manual for a complete list
of format placeholders.
- Sylvie