On Sun, Feb 21, 2016 at 12:32 PM, John Keeping <john@xxxxxxxxxxxxx> wrote:
> GNU grep 2.23 detects the input used in this test as binary data so it
> does not work for extracting lines from a file. We could add the "-a"
> option to force grep to treat the input as text, but not all
> implementations support that. Instead, use sed to extract the desired
> lines since it will always treat its input as text.
>
> Signed-off-by: John Keeping <john@xxxxxxxxxxxxx>
> ---
> diff --git a/t/t9200-git-cvsexportcommit.sh b/t/t9200-git-cvsexportcommit.sh
> @@ -35,7 +35,7 @@ exit 1
> check_entries () {
> # $1 == directory, $2 == expected
> - grep '^/' "$1/CVS/Entries" | sort | cut -d/ -f2,3,5 >actual
> + sed -ne '\!^/!p' "$1/CVS/Entries" | sort | cut -d/ -f2,3,5 >actual
This works with BSD sed, but double negatives are confusing. Have you
considered this instead?
sed -ne '/^\//p' ...
> if test -z "$2"
> then
> >expected
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