Hello,
I'm trying to find /all/ commits that change a file in the
repository...and its proving to be trickier than I thought. :-)
The situation that we were dealing with is this:
- Person A and person B both pull from the same central repository.
- Person A makes a change to file foo.txt and bar.txt, commits, and pushes
to the central repository.
- Person B makes a similar change to bar.txt and commits it.
- Person B does a fetch and merge. Since both A and B made changes to
bar.txt, this requires conflicts to be resolved manually.
- B reverts A's changes to foo.txt. (If B is coming from a different
revision control system, this may happen due to confusion about how merges
are handled.)
- B commits the changes.
- B makes more changes to bar.txt, commits them, and pushes to the central
repository.
At this point, A's changes to foo.txt have been undone.
Graphically:
A1
/ ^
v \
C1 B2<-B3
^ /
\ v
B1
B1, B2, and B3 have the same version of foo.txt as C1, A1 modifies it.
Person A discovers that his changes are missing and wants to know what
happened.
git log foo.txt doesn't help; it won't even show commit A1, due to history
simplification.
git log --full-history foo.txt will show commit A1. It still won't show
commit B2, though, which we'd also like to show (because that's where the
change to foo.txt got removed).
I would think that git log --simplify-merges foo.txt would have done what
I'd wanted, but it still does not show commit B2. Based on what I'm
reading in the man page, I would expect the simplification to go like
this:
A1
| ^
| \
| B2<-B3
| /
v v
C1
(since B1 is TREESAME as C1 if we're only considering foo.txt)
A1
| ^
| \
| B2<-B3
|
v
C1
(since C1 is an ancestor of A1)
However, the actual output only includes A1, not B2.
- Can someone explain this, and/or
- can someone offer a command to display all commits (including merges)
in which ANY parent is not TREESAME?
Thanks!
- Neal
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