Re: Support for __VA_OPT__ in gcc

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On 9/30/2019 9:34 AM, Jonathan Wakely wrote:
On Mon, 30 Sep 2019 at 14:20, Edward Diener
<eldlistmailingz@xxxxxxxxxxxxxx> wrote:

On 9/30/2019 6:08 AM, Jonathan Wakely wrote:
On Sat, 28 Sep 2019 at 04:29, Edward Diener wrote:

Given this program:

#define PP_THIRD_ARG(a,b,c,...) c
#define VA_OPT_SUPPORTED_I(...) PP_THIRD_ARG(__VA_OPT__(,),1,0,)
#define VA_OPT_SUPPORTED() VA_OPT_SUPPORTED_I(?)

#include <iostream>

int main()
        {
        int result = VA_OPT_SUPPORTED();
        std::cout << result;
        return 0;
        }

as a test for __VA_OPT__ support in a C++ compiler ( taken from
https://stackoverflow.com/questions/48045470/portably-detect-va-opt-support
)
I have discovered that __VA_OPT__ support started with gcc-8.1.

You could also consult
https://gcc.gnu.org/projects/cxx-status.html#cxx2a which notes that
the support is incomplete.

However
I have also discovered that the support occurs no matter what the C++
standard level is used for the compilation and not just when the option
is 'std=c++2a'. In other words I can compile the program with
'std=c++03', link and run the program and the program will output 1,
showing __VA_OPT__ support, rather than 0, which shows that __VA_OPT__
is not supported.

If I compile the above with any version of gcc lower than gcc-8.1 the
program will outpyt 0 no matter what -std mode I use.

Is this intended, that the C++20 __VA_OPT__ support works in all modes
for gcc-8.1 and higher ?

Yes, it's available as a GNU extension. You can get a diagnostic with
-std=c++14 -Wpedantic, but not with any -std=gnu++NN modes.

I would strongly argue that if it is available as a GNU extension
outside of normal C++20 support in gcc 8.1 on up then it should be
available when specifying '-std=gnu++nn' but not available when
specifying '-std=c++nn' for any C++ level except for '-std=c++2a'. Isn't
the idea of gnu extensions that they should only be available when the
programmer is using a gnu compiler mode, but not available if a
programmer is using a c++ compiler mode ?

No, absolutely not. The manual seems clear on that point:

"The compiler can accept several base standards, such as ‘c90’ or
‘c++98’, and GNU dialects of those standards, such as ‘gnu90’ or
‘gnu++98’. When a base standard is specified, the compiler accepts all
programs following that standard plus those using GNU extensions that
do not contradict it. For example, -std=c90 turns off certain features
of GCC that are incompatible with ISO C90, such as the asm and typeof
keywords, but not other GNU extensions that do not have a meaning in
ISO C90, such as omitting the middle term of a ?: expression."

So if a programmer compiles using "-std=c++11" gcc feels it has a perfect right to add to its C++11 implementation some feature of C++14 ( or any other C++ standard for that matter ) which does not have any meaning in C++11, as a GNU extension, without the programmer having to specify "-std=gnu++11"? I understand that this is what is specified in your manual but I think such an approach is wrong. If I as a programmer specify a version of the standard, that is what I expect to get, not some amalgam of other standard constructs which would normally have no meaning in the C++ standard I am using.

I am arguing that in principle that gcc's approach, in this regard, is wrong from the end-users point of view while fully conceding that it is what is specified in your manual from which you quote above.




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