Hi, I would like to ask how properly const_double expression should be used inside const_vector? Currently I want to write RTL with vector consisting of 2 DF elements that are zeros, but documentation regarding const_double is not so clear for me. >From const_vector description I know something like this can be done with const_int: (const_vector:V2DF [(const_int 0) (const_int 0)]) but, const_double has different syntax, than const_int: (const_double:m i0 i1 ...). I don't understand what i0, i1 are and there are only two sentences mentioning them: If m is VOIDmode, the bits of the value are stored in i0 and i1. i0 is customarily accessed with the macro CONST_DOUBLE_LOW and i1 with CONST_DOUBLE_HIGH. I tried to find any example in current GCC sources, but apparently there isn't one. I would greatly appreciate explanation on how to use const_double in such case. Thanks, Sebastian
