On Fri, 2016-04-15 at 18:06 -0700, Barry Gold wrote:
> I've written a program that uses the STL, and recently came across
> the
> concept of automatic type determination. Which I think is *brilliant*
> btw.
>
> My code includes the following:
>
> In game.h:
> map<string, string> idlist;
>
> In Game.cpp:
> void Game::addID(string id)
> {
> auto eltp = idlist.find(id);
> if (eltp == map::end) {
> idlist.insert(pair<string,string>(id, id));
> } else {
> // Found in map, so it's a duplicate
> string emsg = "Duplicate ID: %s";
> emsg += id;
> yyerror(emsg);
> }
> }
>
> =====
>
> My make log includes the following error message:
>
> g++ -c -o Game.o Game.cpp
> Game.cpp: In member function ‘void Game::addID(std::string)’:
> Game.cpp:12:10: error: ‘eltp’ does not name a type
> auto eltp = idlist.find(id);
> ^
> Game.cpp:13:9: error: ‘eltp’ was not declared in this scope
> if (eltp == map::end) {
> ^
>
> This seems to imply that g++ is using the old meaning of "auto":
> allocate the variable on the stack. Yet my gcc/g++ identifies as
> version
> 5.3.0, which the docs claim supports C++ version 11.
>
> Do I have to add a command-line flag to enable C++ version 11 and/or
> the
> new meaning of "auto"?
>
Yes, you have to add -std=c++11 to the list of g++ options to enable
C++11 support.
Cheers,
Oleg
