You'll probably need to add the flag: -std=c++11
On Sat, Apr 16, 2016 at 9:06 AM, Barry Gold <barrydgold@xxxxxxxxx> wrote:
> I've written a program that uses the STL, and recently came across the
> concept of automatic type determination. Which I think is *brilliant* btw.
>
> My code includes the following:
>
> In game.h:
> map<string, string> idlist;
>
> In Game.cpp:
> void Game::addID(string id)
> {
> auto eltp = idlist.find(id);
> if (eltp == map::end) {
> idlist.insert(pair<string,string>(id, id));
> } else {
> // Found in map, so it's a duplicate
> string emsg = "Duplicate ID: %s";
> emsg += id;
> yyerror(emsg);
> }
> }
>
> =====
>
> My make log includes the following error message:
>
> g++ -c -o Game.o Game.cpp
> Game.cpp: In member function ‘void Game::addID(std::string)’:
> Game.cpp:12:10: error: ‘eltp’ does not name a type
> auto eltp = idlist.find(id);
> ^
> Game.cpp:13:9: error: ‘eltp’ was not declared in this scope
> if (eltp == map::end) {
> ^
>
> This seems to imply that g++ is using the old meaning of "auto": allocate
> the variable on the stack. Yet my gcc/g++ identifies as version 5.3.0, which
> the docs claim supports C++ version 11.
>
> Do I have to add a command-line flag to enable C++ version 11 and/or the new
> meaning of "auto"?
>
> FWIW, I'm using gcc in the gcc package of cygwin 2.5.0 (32-bit)
>
>
>
> --
> On Beta, we'd have earrings for that. You could buy them in any jewelry
> store. http://www.conchord.org/xeno/bdgsig.html
--
Best regards,
Daniël Bos
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