Re: __attribute__((packed)) seems to break pointer arithmetic

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Also noticed that with -O3 it produces correctly working code in both cases.

Maxim


On 19 February 2013 12:02, Maxim Yegorushkin
<maxim.yegorushkin@xxxxxxxxx> wrote:
> Hi gcc-help,
>
> I stumbled upon strange behaviour of pointer arithmetic when
> __attribute__((packed)) is used. Please consider the following:
>
>     $ cat test.cc
>     #include <cstdio>
>     #include <cstdint>
>
>     struct __attribute__((packed)) Xyz {
>         uint32_t seq_no;
>         uint64_t end_offset;
>     };
>
>     struct Mapping {
>         void* mem;
>         size_t len;
>
>         template<class T>
>         T* begin() {
>             return static_cast<T*>(mem);
>         }
>
>         template<class T>
>         T* end() {
>             auto e = reinterpret_cast<uintptr_t>(static_cast<char*>(mem) + len);
>             return reinterpret_cast<T*>(e - e % sizeof(T));
>         }
>     };
>
>     int main() {
>         Mapping m{reinterpret_cast<void*>(0x40000u), 0x1000u};
>         Xyz* beg = m.begin<Xyz>();
>         Xyz* end = m.end<Xyz>();
>         size_t len = end - beg;
>         printf("%p\n", beg);
>         printf("%p\n", end);
>         printf("%zx\n", len);
>     }
>
>     $ g++ -o test -std=gnu++11 -Wall -Wextra test.cc
>
>     $ ./test
>     0x40000
>     0x40ff8
>     55555555555556aa <---- wrong
>
> When __attribute__((packed)) is removed it correctly outputs:
>
>     $ ./test
>     0x40000
>     0x41000
>     100
>
> I checked the documentation for __attribute__((packed)) and it says
> nothing about it changing the behaviour of pointer arithmetic. Could
> anyone shed some light on this strange behaviour please?
>
> -- Maxim


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