On Wed, Jan 9, 2013 at 10:19 AM, horseriver <horserivers@xxxxxxxxx> wrote: > > here is the disassembly code , > > 629: 0f 84 0e 01 00 00 je 73d <acpi_ec_add+0x125> > 62f: 68 d0 00 00 00 push $0xd0 > 634: ff 35 10 00 00 00 pushl 0x10 > 63a: e8 fc ff ff ff call 63b <acpi_ec_add+0x23> > 63f: 89 c3 mov %eax,%ebx > 641: 5f pop %edi > 642: 58 pop %eax > 643: b8 f4 ff ff ff mov $0xfffffff4,%eax > > > look at the code at 63a address : > > 63a: e8 fc ff ff ff call 63b <acpi_ec_add+0x23> > > e8 is a CALL instruction , but , obviously , 63b is not a subroutin address ,so how does this "call 63b " generate? > > amd what does it do ? You are looking at an object file, not an executable. There is a relocation associated with that address. The linker will use the relocation to fill in the final address when you link the object file into an executable. If you are using "objdump -d" to get the above disassembly, use "objdump -dr" to also see the relocation information. Ian
