On 31 May 2012 02:42, Christopher Sigman <c.s.sigman@xxxxxxxxx> wrote:
> Hi everyone,
>
> Attached is some example code that exhibits the issue. In terms of
A simpler example is
struct __attribute__ ((visibility("hidden"))) Hidden
{
int something;
};
template <typename T>
struct Visible
{
Hidden inner;
};
int main()
{
Visible<int> i;
}
> GCC versions, I think we've seen it in everything from 4.1.2 on, but I
> know for a fact that I see it in 4.4.x, and 4.5.1. I know that if I
It's still present in the latest versions.
> add -fvisibility=hidden to compilation of anything linking to the
> library resolves the warning,
That's because it gives Visible<int> hidden visibility.
> but as I said before, I'm trying to
> understand why we're getting the warning with it as it is (in our
> actual code, we can't set the default visibility to hidden on
> libraries or executables linking to those libraries at the moment).
The compiler is warning you that if you're trying to make Visible<int>
visible outside a shared library then one of its members has hidden
visibility and can't be exported. It's irrelevant that it's a private
member.
