Thanks for your suggestion.
I am trying to comment the following line
new (&buf_cout) stdio_filebuf<char>(stdout, ios_base::out);
new (&buf_cin) stdio_filebuf<char>(stdin, ios_base::in);
new (&buf_cerr) stdio_filebuf<char>(stderr, ios_base::out);
// cout.rdbuf(&buf_cout);
cin.rdbuf(&buf_cin);
cerr.rdbuf(&buf_cerr);
clog.rdbuf(&buf_cerr);
#ifdef _GLIBCXX_USE_WCHAR_T
new (&buf_wcout) stdio_filebuf<wchar_t>(stdout, ios_base::out);
new (&buf_wcin) stdio_filebuf<wchar_t>(stdin, ios_base::in);
new (&buf_wcerr) stdio_filebuf<wchar_t>(stderr, ios_base::out);
// wcout.rdbuf(&buf_wcout);
wcin.rdbuf(&buf_wcin);
I am trying to comment at two places above. and building my gcc.
Thanks
On Fri, Jan 6, 2012 at 3:16 PM, Jonathan Wakely <jwakely.gcc@xxxxxxxxx> wrote:
> On 6 January 2012 09:45, Jonathan Wakely wrote:
>> On 6 January 2012 09:28, naveen yadav wrote:
>>> Dear All,
>>>
>>> I want to modify cout source code in GCC such that it will not print
>>> any thing on the screen.
>>>
>>> The reason is I have very large already compile code(distrubited in
>>> lib form) and it is not possible to recompile. so i left with no
>>> option but to modify in GCC code. Will you pls let me know where I can do it .
>>
>>
>> Can't you just redirect the program's output to /dev/null when you run
>> the program?
>>
>> Or close the file descriptor in your program's main() function?
>>
>> Or duplicate the file descriptor in main() to redirect the output to a file?
>
> Or replace std::cout's streambuf with a different streambuf that
> doesn't write to stdout.
>
> I could probably think of more ways to do it without altering the
> standard library.
