I see the following warning: "assuming signed overflow does not occur when simplifying conditional to constant" pointing to a line containing: if (iRv == SSLSOCK_S_SUCCEED) where: typedef signed int TInt32; TInt32 iRv; #define SSLSOCK_S_SUCCEED 0 Is there any chance for overflow? I'm using gcc-4.6.0 and warning appears as early as -Wstrict-overflow=2 (there is still 3, 4 and 5 - I don't even want to go there). In preprocessed sources, this is: "if (iRv == 0)", so not rogue #defines this time. -- JÄdrzej Dudkiewicz I really hate this damn machine, I wish that they would sell it. It never does just what I want, but only what I tell it.
