J'ai mal aux cuisses et aux fesses aujourd'hui. C'est comme si j'avais fait du sport hier :)) Dr Eric Fernandez Project Leader Physiomics plc The Magdalen Centre The Oxford Science Park Oxford OX4 4GA UK Tel: +44 (0)1865 784986 Web: http://www.physiomics-plc.com Physiomics plc (Company # 4225086, VAT# GB 778 7496 48) is registered in England and Wales at The Magdalen Centre, The Oxford Science Park, Robert Robinson Avenue, Oxford OX4 4GA > -----Original Message----- > From: gcc-help-owner@xxxxxxxxxxx [mailto:gcc-help-owner@xxxxxxxxxxx] > On Behalf Of Marc Glisse > Sent: 18 March 2011 17:04 > To: Matthias Kretz > Cc: gcc-help@xxxxxxx > Subject: Re: function overloading on __restrict__ > > On Fri, 18 Mar 2011, Matthias Kretz wrote: > > > it seems overloading on __restrict__ is not possible. I.e. GCC > > complains > > about: > > void foo(float *__restrict__ mem) const; void foo(float *mem) const; > > > > This, to me, seems to have a very valid use case. Also the AIX C++ > > compiler docs ( > > > http://publib.boulder.ibm.com/infocenter/comphelp/v7v91/index.jsp?topi > > > c=%2Fcom.ibm.vacpp7a.doc%2Flanguage%2Fref%2Fclrc03restrict_type_quali > f > > ier.htm) specify "The __restrict__ qualifier also affects parameter > > type specifications for overloaded functions in the same way as a > > cv-qualifier, thereby affecting the overload set." > > Please read this page more carefully. > > void foo(float *const mem) const; > void foo(float *mem) const; > fails. > > void foo(float *__restrict__* mem) const; void foo(float **mem) const; > works. > > -- > Marc Glisse
