On Fri, 18 Feb 2011, Ian Lance Taylor wrote:
zhang qingshan <steven.zhang54373@xxxxxxxxx> writes:
/* ------- test case -------------------*/
void x();
template <typename T>
void foo(const T*);
int main() {
foo(x);
}
GCC 4.5 complains:
a.cpp: In function 'int main()':
a.cpp:6: error: no matching function for call to 'foo(void (&)())'
It seems that, const T * is resolved as void (&)());
IMO, T --> void (), const T --> void (), const T * --> void (*)(), and
it should be leagle.
You are confusing function pointers with pointers to data objects. They
are not the same thing in C++. That is, a function pointer is not a
special type of pointer.
Well it still kind of is. Without the "const", the code compiles fine. But
the fact that a const qualifier on a function type is ignored seems not to
apply to template type deduction.
(note that most compilers behave like g++ here, except for clang which
accepts the original code)
--
Marc Glisse