Please forgive me for potentially silly question that may not help
Mark
speedup his program. If I understand the "const" keyword, it
tells the
computer that after a const variable gets its first value, that
variable's value will be unchangeable. So I wonder why our friend
has
declared some const variables inside a for-loop and why those
variables
appear on the left sides of the assignment operator inside that loop.
Silly question: Could Mark's computer be wasting time by trying to
change the value of a variable that already has an unchangeable
value?
No, const simply asks the compiler to notify you when you write
code which changes the value.
Modifying an object via a const lvalue is a constraint violation; any
program that does this is not a valid C program.
Modifying a const object via a non-const lvalue is undefined behaviour.
Segher