Hajo Münzer wrote:
> Hi experts,
>
> I'm not sure whether it is a gcc bug or a feature. In the following
> enum's (see code below) the en1 and en2 are converted to a 64 bit type
> ("long long int" in i686 GNU/Linux or "long int" in x86_64 GNU/Linux).
> However, if printing it directly via the first printf command, the
> numbers are interpreted as a 32 bit type.
>
> As a result I get the following output:
> 1 << 31: 80000000, 0xffffffff: ffffffff
> Enums: ffffffff80000000, ffffffff
> Code enums.cpp (32 bit version):
>
> -------------------------------
>
> #include <stdio.h>
>
> enum
> {
> en1 = 1 << 31 /*0x80000000*/
> ,en2 = 0xffffffff
>
> };
>
> int main ()
> {
> printf("1 << 31: %x, 0xffffffff: %x \n", 1 << 31, 0xffffffff);
> printf("Enums: %llx, %llx \n", en1, en2);
> }
>
> ------------------------------
>
> For 64 bit the second printf should be replaced by:
> printf("Enums: %lx, %lx, \n", en1, en2);
>
> I compiled it with:
> g++ -g -o enums.cpp enums.cpp
>
> Has anybody an idea, why the enum types are converted to 64 bit?
You're using the %ll specifier, but you're passing an int. This is wrong.
The type of data must match the printf specifier.
Compile your program with -Wall.
Andrew.
