Hi experts,
I'm not sure whether it is a gcc bug or a feature. In the following
enum's (see code below) the en1 and en2 are converted to a 64 bit type
("long long int" in i686 GNU/Linux or "long int" in x86_64 GNU/Linux).
However, if printing it directly via the first printf command, the
numbers are interpreted as a 32 bit type.
As a result I get the following output:
1 << 31: 80000000, 0xffffffff: ffffffff
Enums: ffffffff80000000, ffffffff
Code enums.cpp (32 bit version):
-------------------------------
#include <stdio.h>
enum
{
en1 = 1 << 31 /*0x80000000*/
,en2 = 0xffffffff
};
int main ()
{
printf("1 << 31: %x, 0xffffffff: %x \n", 1 << 31, 0xffffffff);
printf("Enums: %llx, %llx \n", en1, en2);
}
------------------------------
For 64 bit the second printf should be replaced by:
printf("Enums: %lx, %lx, \n", en1, en2);
I compiled it with:
g++ -g -o enums.cpp enums.cpp
Has anybody an idea, why the enum types are converted to 64 bit?
Thanks a lot,
Hajo
