Re: function with side effects ignored

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Andrew Haley wrote:
Matthew Woehlke wrote:
Using gcc-4.3.2-7.x86_64 (Fedora 10).

I have these functions:

void my_ntoh_float(float *f)
{
  int p = (int*)f;
  *p = ntohl(*p);
}
[snip snip]

Is the bug in the code, or in gcc? In either case, is there a way
(besides dropping optimizations) to fix this that doesn't involve
non-portable code?

It's in your code.  You're accessing an object (p) as an incompatible type.
See C99, Section 6.3.2.3 for all the details.

That's what I suspected.

Do this:

float my_ntoh_float(float f)
{

That should be 'float * f'.

  union
  {
    int i;
    float f;
  } u;

D'oh, should have thought of that. Brain must not be working :-).

Anyway, I saw Brian's reply first, and already got it working with a variant of this (i.e. not changing the signature of my_ntoh_float, which I can't do for compatibility reasons!!). Thanks both for the quick replies!

Which generates this:

my_get_float:
	pushl	%ebp
	movl	%esp, %ebp
	subl	$4, %esp
	movl	8(%ebp), %eax
	movl	(%eax), %eax
	bswap %eax
	movl	%eax, -4(%ebp)
	flds	-4(%ebp)
	leave
	ret

Hmm, I still get this:

ror    $0x8,%ax
ror    $0x10,%eax
ror    $0x8,%ax

...which is interesting. Are you building 32-bit code? Looks like I maybe need to see if there is a -march that we aren't using that might help our performance (not just here, but in general).

(I do get bswap with 64-bit code.)

--
Matthew
Please do not quote my e-mail address unobfuscated in message bodies.
--
"It's not easy for [Microsoft] to accept [competing fairly]"
  -- Dave Heiner (a Microsoft VP, paraphrased)

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