Sorry for beeing so eager on this example, but i have compiled the testcase with following command: g++ -W -Wall -Wextra -Wconversion -pedantic -o test test.cpp test.cpp: In function ‘int main()’: test.cpp:3: warning: unused variable ‘d’ And g++ does not warn about this implicit conversion. Have i missed something? Best regards Martin -------- Original-Nachricht -------- > Datum: Thu, 02 Jul 2009 14:59:44 -0700 > Von: Ian Lance Taylor <iant@xxxxxxxxxx> > An: "Martin Ettl" <ettl.martin@xxxxxx> > CC: gcc-help@xxxxxxxxxxx > Betreff: Re: missing g++ warning about bad allocation > "Martin Ettl" <ettl.martin@xxxxxx> writes: > > > i was not aware of -Wconversion flag. Never the less i was wondering > > that this code was compilable. Because, allocting a negative amount of > > memory does not make senense. Anyway, thanks for the help. > > Since the value is unsigned, you aren't allocating a negative amount of > memory. The -100 is implicitly converted to an unsigned value (on a > 32-bit machine, 0xffffff9c). You are actually trying to allocate a very > large amount of memory, which won't work, but isn't nonsensical. > > -Wconversion warns about the implicit convertsion of the negative > integer to an unsigned type. > > Ian -- GRATIS für alle GMX-Mitglieder: Die maxdome Movie-FLAT! Jetzt freischalten unter http://portal.gmx.net/de/go/maxdome01
