On 1/21/09, John Fine <johnsfine@xxxxxxxxxxx> wrote: > Lawrence Crowl wrote: > > > holderlin wrote: > > > > Is there any difference between (*(x)).a and (x)->a, if x is an > > > > expression which generates a struct pointer. > > > > They are the same for the C language, but may be different in C++ > > if the struct has overloaded the * or -> operators. > > Can they be different in C++ ? > > A key phrase in the question is "x is an expression which generates > a struct pointer." > > You can overload the meaning of * or -> if x is a struct. I thought > you couldn't overload them if x is a pointer. Yes, you're right. I somehow glossed over the constraint. -- Lawrence Crowl
