Lawrence Crowl wrote:
holderlin wrote:Is there any difference between (*(x)).a and (x)->a, if x is an expression which generates a struct pointer.They are the same for the C language, but may be different in C++ if the struct has overloaded the * or -> operators.
Can they be different in C++ ?A key phrase in the question is "x is an expression which generates a struct pointer."
You can overload the meaning of * or -> if x is a struct. I thought you couldn't overload them if x is a pointer.
