John Love-Jensen wrote:
Hi Yang Zhang,
cout << typeid(int64_t).name() << endl;
cout << typeid(long long).name() << endl;
This prints:
l
x
What does this mean?
This means that they are not the same type.
HTH,
--Eljay
You're right, of course, and I knew they were different already, without
needing to see the above output. I just wasn't sure if that was the
correct/expected output (I was assuming I'd get a more human-friendly name).
Steering this thread back on track: I'm still not sure why these are
different. So far, I know that both long long and int64_t are 64-bit
signed integral types. They still don't have to actually be the same
type, but I was hoping someone would be able to explain things to a bit
more depth (e.g. rationale).
--
Yang Zhang
http://www.mit.edu/~y_z/
