On 7/1/08 2:17 PM, "Yang Zhang" <yanghatespam@xxxxxxxxx> wrote: > Hi, why isn't int64_t == long long at least on 64-bit x86 Linux? Because int64_t should be 64-bit, but long long could be 64-bit or larger. #include <stdint.h> // from C99 #include <climits> cout << (sizeof(int64_t) * CHAR_BIT) << endl; cout << (sizeof(long long) * CHAR_BIT) << endl; You can also do this: #include <stdint.h> // from C99 #include <typeinfo> cout << typeid(int64_t).name() << endl; cout << typeid(long long).name() << endl; > How do I tell what type this actually is? typeid > And are literals ending with LL always long long? Yes, that's what the LL suffix means. So the literal integer numerics are: 'A' L'A' 65 65L 65LL 65U 65UL 65ULL Keep in mind the portability issues surrounding use of long long, LL, and ULL. You may want to use the <stdint.h> INT64_C and UINT64_C macros to construct your numeric literals. INT64_C(65) UINT64_C(65) HTH, --Eljay
