Scott,
I just tried the following:
a = (unsigned short) ( a + 1 ) % b;
which appears to work as you expect. I tried it using gcc 3.4.4 on
Windows (Cygwin).
Good luck!
--
Tony Wetmore
Raytheon Solipsys
Scott Phuong wrote:
I see. Well, thank you very much for your help. I appreciate the quick response.
Scott
On Mon, Jun 2, 2008 at 7:11 PM, me22 <me22.ca@xxxxxxxxx> wrote:
On Mon, Jun 2, 2008 at 10:04 PM, Scott Phuong <mycleanjunk@xxxxxxxxx> wrote:
Thanks so much for your quick reply. This code is simliar to code in a
third party source code that I have to fix and they do this all over
the place. The question is w/o touching their code is there a way I
can fix this?
Switch to a platform with 16-bit ints?
I tried explicitly casting the 1 to an unsigned short
but it doesn't seem to work like this:
a = (a + (unsigned short) 1) % b.
More evidence that you're hitting integral promotion, so there's
basically nothing you can do about it.
(Besides make sure a is never that large :P)
